(1/3)(9x-42)-5x=-70

Solution for (1/3)(9x-42)-5x=-70 equation:

(1/3)(9x-42)-5x=-70

We move all terms to the left:

(1/3)(9x-42)-5x-(-70)=0


Domain of the equation: 3)(9x-42)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(9x-42)-5x-(-70)=0

We add all the numbers together, and all the variables

-5x+(+1/3)(9x-42)+70=0

We multiply parentheses ..

(+9x^2+1/3*-42)-5x+70=0

We multiply all the terms by the denominator


(+9x^2+1-5x*3*-42)+70*3*-42)=0

We add all the numbers together, and all the variables

(+9x^2+1-5x*3*-42)=0

We get rid of parentheses

9x^2-5x*3*+1-42=0

We add all the numbers together, and all the variables

9x^2-5x*3*-41=0

Wy multiply elements

9x^2-15x^2-41=0

We add all the numbers together, and all the variables

-6x^2-41=0

a = -6; b = 0; c = -41;
Δ = b2-4ac
Δ = 02-4·(-6)·(-41)
Δ = -984
Delta is less than zero, so there is no solution for the equation