(1/3)(6p-12)=5

Solution for (1/3)(6p-12)=5 equation:

(1/3)(6p-12)=5

We move all terms to the left:

(1/3)(6p-12)-(5)=0


Domain of the equation: 3)(6p-12)!=0

p∈R


We add all the numbers together, and all the variables

(+1/3)(6p-12)-5=0

We multiply parentheses ..

(+6p^2+1/3*-12)-5=0

We multiply all the terms by the denominator


(+6p^2+1-5*3*-12)=0

We get rid of parentheses

6p^2+1-12-5*3*=0

We add all the numbers together, and all the variables

6p^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{12}=0$