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(1/3)(2x-4)+5=(-2/3)(x+1)
We move all terms to the left:
(1/3)(2x-4)+5-((-2/3)(x+1))=0
Domain of the equation: 3)(2x-4)!=0
x∈R
Domain of the equation: 3)(x+1))!=0We add all the numbers together, and all the variables
x∈R
(+1/3)(2x-4)-((-2/3)(x+1))+5=0
We multiply parentheses ..
(+2x^2+1/3*-4)-((-2/3)(x+1))+5=0
We calculate fractions
((+2x^2+1*3)(x+1)))/(-4)*3)(x+1))+3*)+()/(-4)*3)(x+1))+3*)+5=0
We calculate fractions
(((+2x^2+1*3)(x+1)))*(-4)*3)(x+1))+3*)+5)/((*(-4)*3)(x+1))+3*)+5)+(-4)*3)(x+1))+3*)+()*()/((*(-4)*3)(x+1))+3*)+5)=0
We can not solve this equation
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