(1/3)(21x+39)=-36

Solution for (1/3)(21x+39)=-36 equation:

(1/3)(21x+39)=-36

We move all terms to the left:

(1/3)(21x+39)-(-36)=0


Domain of the equation: 3)(21x+39)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(21x+39)-(-36)=0

We add all the numbers together, and all the variables

(+1/3)(21x+39)+36=0

We multiply parentheses ..

(+21x^2+1/3*39)+36=0

We multiply all the terms by the denominator


(+21x^2+1+36*3*39)=0

We get rid of parentheses

21x^2+1+36*3*39=0

We add all the numbers together, and all the variables

21x^2+4213=0

a = 21; b = 0; c = +4213;
Δ = b2-4ac
Δ = 02-4·21·4213
Δ = -353892
Delta is less than zero, so there is no solution for the equation