(1/3)(15-6x)=4-2x

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Solution for (1/3)(15-6x)=4-2x equation: 


x in (-oo:+oo)

(1/3)*(15-(6*x)) = 4-(2*x) // - 4-(2*x)

(1/3)*(15-(6*x))+2*x-4 = 0

(1/3)*(15-6*x)+2*x-4 = 0

1/3*(15-6*x)+2*x-4 = 0

1/3*(15-6*x)+2*x-4 = 0

5-4 = 0

1 = 0

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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