(1/3)^(7x-1)=27

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Solution for (1/3)^(7x-1)=27 equation: 



(1/3)^(7x-1)=27

We move all terms to the left:

(1/3)^(7x-1)-(27)=0



Domain of the equation: 3)^(7x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^(7x-1)-27=0

We multiply all the terms by the denominator


(+1-27*3)^(7x-1)=0

We add all the numbers together, and all the variables

(-80)^(7x-1)=0

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