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(1/3(x))+(x)=180
We move all terms to the left:
(1/3(x))+(x)-(180)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3x)+x-180=0
We add all the numbers together, and all the variables
x+(+1/3x)-180=0
We get rid of parentheses
x+1/3x-180=0
We multiply all the terms by the denominator
x*3x-180*3x+1=0
Wy multiply elements
3x^2-540x+1=0
a = 3; b = -540; c = +1;
Δ = b2-4ac
Δ = -5402-4·3·1
Δ = 291588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291588}=\sqrt{8836*33}=\sqrt{8836}*\sqrt{33}=94\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-94\sqrt{33}}{2*3}=\frac{540-94\sqrt{33}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+94\sqrt{33}}{2*3}=\frac{540+94\sqrt{33}}{6} $
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