(1/2x+6)2=(x-3)3

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Solution for (1/2x+6)2=(x-3)3 equation: 



(1/2x+6)2=(x-3)3

We move all terms to the left:

(1/2x+6)2-((x-3)3)=0



Domain of the equation: 2x+6)2!=0

x∈R



We multiply parentheses

2x-((x-3)3)+12=0



We calculate terms in parentheses: -((x-3)3), so:

(x-3)3

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We get rid of parentheses

2x-3x+9+12=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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