(1/2x+4)-(4/3x)=(2/x+2)

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Solution for (1/2x+4)-(4/3x)=(2/x+2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x-((4/3)*x)+4 = 2/x+2 // - 2/x+2

(1/2)*x-((4/3)*x)-(2/x)-2+4 = 0

(1/2)*x+(-4/3)*x-2*x^-1-2+4 = 0

2*x^0-5/6*x^1-2*x^-1 = 0

(2*x^1-5/6*x^2-2*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-5/6*x^2-2*x^0) = 0

x^1

(-5/6)*x^2+2*x-2 = 0

(-5/6)*x^2+2*x-2 = 0

DELTA = 2^2-(-2*4*(-5/6))

DELTA = -8/3

DELTA < 0

x in { } 

x belongs to the empty set

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