(1/2x)=(7/4)-(3/x)

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Solution for (1/2x)=(7/4)-(3/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x = 7/4-(3/x) // - 7/4-(3/x)

(1/2)*x+3/x-(7/4) = 0

(1/2)*x+3/x-7/4 = 0

1/2*x^1+3*x^-1-7/4*x^0 = 0

(1/2*x^2-7/4*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2-7/4*x^1+3*x^0) = 0

x^1

(1/2)*x^2+(-7/4)*x+3 = 0

(1/2)*x^2+(-7/4)*x+3 = 0

DELTA = (-7/4)^2-(3*4*(1/2))

DELTA = -47/16

DELTA < 0

x in { } 

x belongs to the empty set

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