(1/2*x)+1+x=100

Solution for (1/2*x)+1+x=100 equation:

(1/2x)+1+x=100

We move all terms to the left:

(1/2x)+1+x-(100)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2x)+x+1-100=0

We add all the numbers together, and all the variables

x+(+1/2x)-99=0

We get rid of parentheses

x+1/2x-99=0

We multiply all the terms by the denominator


x*2x-99*2x+1=0

Wy multiply elements

2x^2-198x+1=0

a = 2; b = -198; c = +1;
Δ = b2-4ac
Δ = -1982-4·2·1
Δ = 39196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39196}=\sqrt{4*9799}=\sqrt{4}*\sqrt{9799}=2\sqrt{9799}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-198)-2\sqrt{9799}}{2*2}=\frac{198-2\sqrt{9799}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-198)+2\sqrt{9799}}{2*2}=\frac{198+2\sqrt{9799}}{4}
$