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(1/2)y+3=y-33
We move all terms to the left:
(1/2)y+3-(y-33)=0
Domain of the equation: 2)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+1/2)y-(y-33)+3=0
We multiply parentheses
y^2-(y-33)+3=0
We get rid of parentheses
y^2-y+33+3=0
We add all the numbers together, and all the variables
y^2-1y+36=0
a = 1; b = -1; c = +36;
Δ = b2-4ac
Δ = -12-4·1·36
Δ = -143
Delta is less than zero, so there is no solution for the equation
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