(1/2)x+1=(3/2)+-8

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Solution for (1/2)x+1=(3/2)+-8 equation: 



(1/2)x+1=(3/2)+-8

We move all terms to the left:

(1/2)x+1-((3/2)+-8)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)x+1-((+3/2)+-8)=0

We use the square of the difference formula

(+1/2)x+1-((+3/2)-8)=0

We multiply parentheses

x^2+1-((+3/2)-8)=0

We multiply all the terms by the denominator


x^2*2)-8)+1*2)-8)-((+3=0

Wy multiply elements

4x^4=0

We do not support expression: x^4

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