(1/2)t+7=(3/2)t-4

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Solution for (1/2)t+7=(3/2)t-4 equation:



(1/2)t+7=(3/2)t-4
We move all terms to the left:
(1/2)t+7-((3/2)t-4)=0
Domain of the equation: 2)t!=0
t!=0/1
t!=0
t∈R
Domain of the equation: 2)t-4)!=0
t!=0/1
t!=0
t∈R
We add all the numbers together, and all the variables
(+1/2)t-((+3/2)t-4)+7=0
We multiply parentheses
t^2-((+3/2)t-4)+7=0
We multiply all the terms by the denominator
t^2*2)t-4)-((+7*2)t-4)+3=0
We add all the numbers together, and all the variables
t^2*2)t-4)-(14t-4)+3=0
Wy multiply elements
2t^3=0
We do not support etpression: t^3

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