(1/2)t+4=1

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Solution for (1/2)t+4=1 equation: 



(1/2)t+4=1

We move all terms to the left:

(1/2)t+4-(1)=0



Domain of the equation: 2)t!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+1/2)t+4-1=0

We add all the numbers together, and all the variables

(+1/2)t+3=0

We multiply parentheses

t^2+3=0

a = 1; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·1·3
Δ = -12
Delta is less than zero, so there is no solution for the equation

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