(1/2)n+10=(2n)-35

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Solution for (1/2)n+10=(2n)-35 equation: 



(1/2)n+10=(2n)-35

We move all terms to the left:

(1/2)n+10-((2n)-35)=0



Domain of the equation: 2)n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+1/2)n-(2n-35)+10=0

We multiply parentheses

n^2-(2n-35)+10=0

We get rid of parentheses

n^2-2n+35+10=0

We add all the numbers together, and all the variables

n^2-2n+45=0

a = 1; b = -2; c = +45;
Δ = b2-4ac
Δ = -22-4·1·45
Δ = -176
Delta is less than zero, so there is no solution for the equation

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