If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1/2)k=0
Domain of the equation: 2)k!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
(+1/2)k=0
We multiply parentheses
k^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{0}{2}=0$
| 3(x+8)=5(3x-12 | | X+2(4x+-4)=8 | | 11=121x | | 4x+(2x-10)+(4x+10)=180 | | (2x+1)^-3/4=27 | | 5.5-2=n | | -63z-1-3=-57 | | 3x+x+16=0 | | x(3)+x+16=0 | | -16=k3+k | | 4k-k-33=0 | | 18.3–4.2r=8.24 | | 9x=81-27 | | -5x-2(-3x+18)=36 | | 2/x-2+5=27/x-2 | | 360=180(n-2) | | (2/x-2)+5=(27/x-2) | | A-3x=0 | | 4x+4(6x+6)=116 | | 2x-(-2x)-6=8 | | 2x-2x-6=8 | | 3x-5(2×-16)=143 | | 0.3n-1.4=0.4-0.2n | | (t+8)=7t+56 | | x+6/18=4/9+x-5/6 | | 24=6/7w | | (x+2)=3x+6 | | x+3/10=4/5+x-1/3 | | 35x4=5xx= | | 7+x=22-2x | | 35x4=5x | | c-7/10=9 |