(1/2)b+(9/4)=(7/8)

Solution for (1/2)b+(9/4)=(7/8) equation:

(1/2)b+(9/4)=(7/8)

We move all terms to the left:

(1/2)b+(9/4)-((7/8))=0


Domain of the equation: 2)b!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

(+1/2)b+(+9/4)-((+7/8))=0

We multiply parentheses

b^2+(+9/4)-((+7/8))=0

We get rid of parentheses

b^2+9/4-((+7/8))=0

We calculate fractions


b^2+()/()+()/()=0

We add all the numbers together, and all the variables

b^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation