(1/2)20x+18=200

Solution for (1/2)20x+18=200 equation:

(1/2)20x+18=200

We move all terms to the left:

(1/2)20x+18-(200)=0


Domain of the equation: 2)20x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)20x+18-200=0

We add all the numbers together, and all the variables

(+1/2)20x-182=0

We multiply parentheses

20x^2-182=0

a = 20; b = 0; c = -182;
Δ = b2-4ac
Δ = 02-4·20·(-182)
Δ = 14560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14560}=\sqrt{16*910}=\sqrt{16}*\sqrt{910}=4\sqrt{910}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{910}}{2*20}=\frac{0-4\sqrt{910}}{40}
=-\frac{4\sqrt{910}}{40}
=-\frac{\sqrt{910}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{910}}{2*20}=\frac{0+4\sqrt{910}}{40}
=\frac{4\sqrt{910}}{40}
=\frac{\sqrt{910}}{10}
$