(1/2)2-3x=7x+8-10x

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Solution for (1/2)2-3x=7x+8-10x equation: 


x in (-oo:+oo)

(1/2)^2-(3*x) = 7*x-(10*x)+8 // - 7*x-(10*x)+8

10*x-(3*x)-(7*x)+(1/2)^2-8 = 0

10*x-3*x-7*x+(1/2)^2-8 = 0

-31/4 = 0

x belongs to the empty set

x belongs to the empty set

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