(1/2)+(2/5)s=s-(3/4)

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Solution for (1/2)+(2/5)s=s-(3/4) equation: 



(1/2)+(2/5)s=s-(3/4)

We move all terms to the left:

(1/2)+(2/5)s-(s-(3/4))=0



Domain of the equation: 5)s!=0

s!=0/1

s!=0

s∈R



We add all the numbers together, and all the variables

(+2/5)s-(s-(+3/4))+(+1/2)=0

We multiply parentheses

2s^2-(s-(+3/4))+(+1/2)=0

We get rid of parentheses

2s^2-(s-(+3/4))+1/2=0

We calculate fractions


2s^2+(-(s-(+3*2)/()+()/()=0



We calculate terms in parentheses: +(-(s-(+3*2)/()+()/(), so:

-(s-(+3*2)/()+()/(

We can not solve this equation

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