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x in (-oo:+oo)
(1/2)*(x/3-(5/6)) = (1/3)*((1/2)*x-2)+1/4 // - (1/3)*((1/2)*x-2)+1/4
(1/2)*(x/3-(5/6))-((1/3)*((1/2)*x-2))-(1/4) = 0
(1/2)*(x/3-5/6)+(-1/3)*((1/2)*x-2)-1/4 = 0
1/2*(1/3*x-5/6)-1/3*(1/2*x-2)-1/4 = 0
(1/2*4*(1/3*x-5/6))/4+(-1/3*4*(1/2*x-2))/4-1/4 = 0
1/2*4*(1/3*x-5/6)-1/3*4*(1/2*x-2)-1 = 0
1-1 = 0
0 = 0
0/4 = 0
0/4 = 0 // * 4
0 = 0
x belongs to the empty set
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