(1/2)(x)(2x+1)=18

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Solution for (1/2)(x)(2x+1)=18 equation: 


x in (-oo:+oo)

(1/2)*x*(2*x+1) = 18 // - 18

(1/2)*x*(2*x+1)-18 = 0

1/2*x*(2*x+1)-18 = 0

1/2*x*(2*x+1)-18 = 0

x^2+1/2*x-18 = 0

x^2+1/2*x-18 = 0

x^2+1/2*x-18 = 0

DELTA = (1/2)^2-(-18*1*4)

DELTA = 289/4

DELTA > 0

x = ((289/4)^(1/2)-1/2)/(1*2) or x = (-(289/4)^(1/2)-1/2)/(1*2)

x = 4 or x = -9/2

(x+9/2)*(x-4) = 0

(x+9/2)*(x-4) = 0

( x+9/2 )

x+9/2 = 0 // - 9/2

x = -9/2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -9/2, 4 }

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