(1/2)(8x-8)=10x+20+2x

Solution for (1/2)(8x-8)=10x+20+2x equation:

(1/2)(8x-8)=10x+20+2x

We move all terms to the left:

(1/2)(8x-8)-(10x+20+2x)=0


Domain of the equation: 2)(8x-8)!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)(8x-8)-(12x+20)=0

We get rid of parentheses

(+1/2)(8x-8)-12x-20=0

We multiply parentheses ..

(+8x^2+1/2*-8)-12x-20=0

We multiply all the terms by the denominator


(+8x^2+1-12x*2*-8)-20*2*-8)=0

We add all the numbers together, and all the variables

(+8x^2+1-12x*2*-8)=0

We get rid of parentheses

8x^2-12x*2*+1-8=0

We add all the numbers together, and all the variables

8x^2-12x*2*-7=0

Wy multiply elements

8x^2-24x^2-7=0

We add all the numbers together, and all the variables

-16x^2-7=0

a = -16; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-16)·(-7)
Δ = -448
Delta is less than zero, so there is no solution for the equation