(1/2)(-5+2x)-7x=-3

Solution for (1/2)(-5+2x)-7x=-3 equation:

(1/2)(-5+2x)-7x=-3

We move all terms to the left:

(1/2)(-5+2x)-7x-(-3)=0


Domain of the equation: 2)(-5+2x)!=0

We move all terms containing x to the left, all other terms to the right

2x)+2)(!=5

x∈R


We add all the numbers together, and all the variables

(+1/2)(2x-5)-7x-(-3)=0

We add all the numbers together, and all the variables

-7x+(+1/2)(2x-5)+3=0

We multiply parentheses ..

(+2x^2+1/2*-5)-7x+3=0

We multiply all the terms by the denominator


(+2x^2+1-7x*2*-5)+3*2*-5)=0

We add all the numbers together, and all the variables

(+2x^2+1-7x*2*-5)=0

We get rid of parentheses

2x^2-7x*2*+1-5=0

We add all the numbers together, and all the variables

2x^2-7x*2*-4=0

Wy multiply elements

2x^2-14x^2-4=0

We add all the numbers together, and all the variables

-12x^2-4=0

a = -12; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-12)·(-4)
Δ = -192
Delta is less than zero, so there is no solution for the equation