(1/12x+1)(1/12x+1)=x+1

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Solution for (1/12x+1)(1/12x+1)=x+1 equation: 


x in (-oo:+oo)

((1/12)*x+1)*((1/12)*x+1) = x+1 // - x+1

((1/12)*x+1)*((1/12)*x+1)-x-1 = 0

(1/12*x+1)^2-x-1 = 0

(1/12*x+1)^2-x-1 = 0

1/144*x^2-5/6*x-1+1 = 0

1/144*x^2-5/6*x = 0

1/144*x^2-5/6*x = 0

1/6*x*(1/24*x-5) = 0

1/24*x-5 = 0 // + 5

1/24*x = 5 // : 1/24

x = 5/1/24

x = 120

1/6*x*(x-120) = 0

1/6*x*(x-120) = 0

( 1/6*x )

1/6*x = 0 // : 1/6

x = 0

( x-120 )

x-120 = 0 // + 120

x = 120

x in { 0, 120 }

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