(1/10+x)+(1/x)=(1/19)

Solution for (1/10+x)+(1/x)=(1/19) equation:

(1/10+x)+(1/x)=(1/19)

We move all terms to the left:

(1/10+x)+(1/x)-((1/19))=0


Domain of the equation: 10+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-10

x!=-10/1

x!=-10

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+x+1/10)+(+1/x)-((+1/19))=0

We get rid of parentheses

x+1/x+1/10-((+1/19))=0

We calculate fractions


19x^2/190x^2+x+()/190x^2+(-((+1*x*10)/190x^2=0

We multiply all the terms by the denominator


19x^2+x*190x^2+(-((+1*x*10)+()=0


We calculate terms in parentheses: +(-((+1*x*10)+(), so:

-((+1*x*10)+(


Wy multiply elements

19x^2+190x^3+(-((+1*x*10)+()=0


We calculate terms in parentheses: +(-((+1*x*10)+(), so:

-((+1*x*10)+(


We do not support expression: x^3