(1/(x-2))+(1(x-4))

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Solution for (1/(x-2))+(1(x-4)) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

1/(x-2)+1*(x-4) = 0

1/(x-2)+x-4 = 0

1/(x-2)+(x*(x-2))/(x-2)+(-4*(x-2))/(x-2) = 0

x*(x-2)-4*(x-2)+1 = 0

x^2-2*x-4*x+1+8 = 0

x^2-6*x+9 = 0

x^2-6*x+9 = 0

x^2-6*x+9 = 0

DELTA = (-6)^2-(1*4*9)

DELTA = 0

x = 6/(1*2)

x = 3 or x = 3

(x-3)^2 = 0

((x-3)^2)/(x-2) = 0

((x-3)^2)/(x-2) = 0 // * x-2

(x-3)^2 = 0

x-3 = 0 // + 3

x = 3

x in { 3, 3 }

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