(1.65*(1+x))/(0.098-x)=19

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Solution for (1.65*(1+x))/(0.098-x)=19 equation: 



(1.65(1+x))/(0.098-x)=19

We move all terms to the left:

(1.65(1+x))/(0.098-x)-(19)=0



Domain of the equation: (0.098-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-0.098

x!=-0.098/-1

x!=0.098/1

x∈R



We add all the numbers together, and all the variables

(1.65(x+1))/(-1x+0.098)-19=0

We multiply all the terms by the denominator


(1.65(x+1))-19*(-1x+0.098)=0



We calculate terms in parentheses: +(1.65(x+1)), so:

1.65(x+1)

We multiply parentheses

1.65x+1.65

Back to the equation:

+(1.65x+1.65)



We multiply parentheses

(1.65x+1.65)+19x-1.862=0

We get rid of parentheses

1.65x+19x+1.65-1.862=0

We add all the numbers together, and all the variables

20.65x-0.212=0

We move all terms containing x to the left, all other terms to the right

20.65x=0.212

x=0.212/20.65

x=0.212/20.65

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