(1.6-x)(x-1)=0

Solution for (1.6-x)(x-1)=0 equation:

(1.6-x)(x-1)=0

We add all the numbers together, and all the variables

(-1x+1.6)(x-1)=0

We multiply parentheses ..

(-1x^2+x+1.6x-1.6)=0

We get rid of parentheses

-1x^2+x+1.6x-1.6=0

We add all the numbers together, and all the variables

-1x^2+2.6x-1.6=0

a = -1; b = 2.6; c = -1.6;
Δ = b2-4ac
Δ = 2.62-4·(-1)·(-1.6)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6)-\sqrt{0.36}}{2*-1}=\frac{-2.6-\sqrt{0.36}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6)+\sqrt{0.36}}{2*-1}=\frac{-2.6+\sqrt{0.36}}{-2}
$