(1.25-x)(0.25-x)=0

Solution for (1.25-x)(0.25-x)=0 equation:

(1.25-x)(0.25-x)=0

We add all the numbers together, and all the variables

(-1x+1.25)(-1x+0.25)=0

We multiply parentheses ..

(+x^2-0.25x-1.25x+0.3125)=0

We get rid of parentheses

x^2-0.25x-1.25x+0.3125=0

We add all the numbers together, and all the variables

x^2-1.5x+0.3125=0

a = 1; b = -1.5; c = +0.3125;
Δ = b2-4ac
Δ = -1.52-4·1·0.3125
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-1}{2*1}=\frac{0.5}{2}
=0.5/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+1}{2*1}=\frac{2.5}{2}
=1+0.5/2
$