(1-x)(-4+4x)=(2x+10)(-2x-22)

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Solution for (1-x)(-4+4x)=(2x+10)(-2x-22) equation: 



(1-x)(-4+4x)=(2x+10)(-2x-22)

We move all terms to the left:

(1-x)(-4+4x)-((2x+10)(-2x-22))=0

We add all the numbers together, and all the variables

(-1x+1)(4x-4)-((2x+10)(-2x-22))=0

We multiply parentheses ..

(-4x^2+4x+4x-4)-((2x+10)(-2x-22))=0



We calculate terms in parentheses: -((2x+10)(-2x-22)), so:

(2x+10)(-2x-22)

We multiply parentheses ..

(-4x^2-44x-20x-220)

We get rid of parentheses

-4x^2-44x-20x-220

We add all the numbers together, and all the variables

-4x^2-64x-220

Back to the equation:

-(-4x^2-64x-220)



We get rid of parentheses

-4x^2+4x^2+4x+4x+64x-4+220=0

We add all the numbers together, and all the variables

72x+216=0

We move all terms containing x to the left, all other terms to the right

72x=-216

x=-216/72

x=-3

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