(1-w)(5w+9)=0

Solution for (1-w)(5w+9)=0 equation:

(1-w)(5w+9)=0

We add all the numbers together, and all the variables

(-1w+1)(5w+9)=0

We multiply parentheses ..

(-5w^2-9w+5w+9)=0

We get rid of parentheses

-5w^2-9w+5w+9=0

We add all the numbers together, and all the variables

-5w^2-4w+9=0

a = -5; b = -4; c = +9;
Δ = b2-4ac
Δ = -42-4·(-5)·9
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*-5}=\frac{-10}{-10}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*-5}=\frac{18}{-10}
=-1+4/5
$