(1-i)z+(2+i)z=2+2i

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Solution for (1-i)z+(2+i)z=2+2i equation:


Simplifying
(1 + -1i) * z + (2 + i) * z = 2 + 2i

Reorder the terms for easier multiplication:
z(1 + -1i) + (2 + i) * z = 2 + 2i
(1 * z + -1i * z) + (2 + i) * z = 2 + 2i

Reorder the terms:
(-1iz + 1z) + (2 + i) * z = 2 + 2i
(-1iz + 1z) + (2 + i) * z = 2 + 2i

Reorder the terms for easier multiplication:
-1iz + 1z + z(2 + i) = 2 + 2i
-1iz + 1z + (2 * z + i * z) = 2 + 2i

Reorder the terms:
-1iz + 1z + (iz + 2z) = 2 + 2i
-1iz + 1z + (iz + 2z) = 2 + 2i

Reorder the terms:
-1iz + iz + 1z + 2z = 2 + 2i

Combine like terms: -1iz + iz = 0
0 + 1z + 2z = 2 + 2i
1z + 2z = 2 + 2i

Combine like terms: 1z + 2z = 3z
3z = 2 + 2i

Solving
3z = 2 + 2i

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Divide each side by '3'.
z = 0.6666666667 + 0.6666666667i

Simplifying
z = 0.6666666667 + 0.6666666667i

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