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(1-5x)(3x+10)=0
We add all the numbers together, and all the variables
(-5x+1)(3x+10)=0
We multiply parentheses ..
(-15x^2-50x+3x+10)=0
We get rid of parentheses
-15x^2-50x+3x+10=0
We add all the numbers together, and all the variables
-15x^2-47x+10=0
a = -15; b = -47; c = +10;
Δ = b2-4ac
Δ = -472-4·(-15)·10
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-53}{2*-15}=\frac{-6}{-30} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+53}{2*-15}=\frac{100}{-30} =-3+1/3 $
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