(1-5i)(2/3-i)

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Solution for (1-5i)(2/3-i) equation: 


i in (-oo:+oo)

(1-(5*i))*(2/3-i) = 0

(1-5*i)*(2/3-i) = 0

( 1-5*i )

1-5*i = 0 // - 1

-5*i = -1 // : -5

i = -1/(-5)

i = 1/5

( 2/3-i )

2/3-i = 0 // - 2/3

-i = -2/3 // * -1

i = 2/3

i in { 1/5, 2/3 }

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