(1-3x)*(1+3x)-2*(x-5)=3-(9x*9x)

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Solution for (1-3x)*(1+3x)-2*(x-5)=3-(9x*9x) equation: 



(1-3x)(1+3x)-2(x-5)=3-(9x*9x)

We move all terms to the left:

(1-3x)(1+3x)-2(x-5)-(3-(9x*9x))=0

We add all the numbers together, and all the variables

(-3x+1)(3x+1)-2(x-5)-(3-(+9x*9x))=0

We multiply parentheses

(-3x+1)(3x+1)-2x-(3-(+9x*9x))+10=0

We multiply parentheses ..

(-9x^2-3x+3x+1)-2x-(3-(+9x*9x))+10=0



We calculate terms in parentheses: -(3-(+9x*9x)), so:

3-(+9x*9x)

determiningTheFunctionDomain
-(+9x*9x)+3

We get rid of parentheses

-9x*9x+3

Wy multiply elements

-81x^2+3

Back to the equation:

-(-81x^2+3)



We get rid of parentheses

-9x^2+81x^2-3x+3x-2x+1-3+10=0

We add all the numbers together, and all the variables

72x^2-2x+8=0

a = 72; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·72·8
Δ = -2300
Delta is less than zero, so there is no solution for the equation

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