(1-3x)(x-8)=0

Solution for (1-3x)(x-8)=0 equation:

(1-3x)(x-8)=0

We add all the numbers together, and all the variables

(-3x+1)(x-8)=0

We multiply parentheses ..

(-3x^2+24x+x-8)=0

We get rid of parentheses

-3x^2+24x+x-8=0

We add all the numbers together, and all the variables

-3x^2+25x-8=0

a = -3; b = 25; c = -8;
Δ = b2-4ac
Δ = 252-4·(-3)·(-8)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-23}{2*-3}=\frac{-48}{-6}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+23}{2*-3}=\frac{-2}{-6}
=1/3
$