(1-3i)(2x+i)=5+yi

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Solution for (1-3i)(2x+i)=5+yi equation: 


Simplifying
(1 + -3i)(2x + i) = 5 + yi

Reorder the terms:
(1 + -3i)(i + 2x) = 5 + yi

Multiply (1 + -3i) * (i + 2x)
(1(i + 2x) + -3i * (i + 2x)) = 5 + yi
((i * 1 + 2x * 1) + -3i * (i + 2x)) = 5 + yi
((1i + 2x) + -3i * (i + 2x)) = 5 + yi
(1i + 2x + (i * -3i + 2x * -3i)) = 5 + yi

Reorder the terms:
(1i + 2x + (-6ix + -3i2)) = 5 + yi
(1i + 2x + (-6ix + -3i2)) = 5 + yi

Reorder the terms:
(1i + -6ix + -3i2 + 2x) = 5 + yi
(1i + -6ix + -3i2 + 2x) = 5 + yi

Solving
1i + -6ix + -3i2 + 2x = 5 + iy

Solving for variable 'i'.

Reorder the terms:
-5 + 1i + -6ix + -1iy + -3i2 + 2x = 5 + iy + -5 + -1iy

Reorder the terms:
-5 + 1i + -6ix + -1iy + -3i2 + 2x = 5 + -5 + iy + -1iy

Combine like terms: 5 + -5 = 0
-5 + 1i + -6ix + -1iy + -3i2 + 2x = 0 + iy + -1iy
-5 + 1i + -6ix + -1iy + -3i2 + 2x = iy + -1iy

Combine like terms: iy + -1iy = 0
-5 + 1i + -6ix + -1iy + -3i2 + 2x = 0

The solution to this equation could not be determined.

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