(1-3i)(1+3i)=0

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Solution for (1-3i)(1+3i)=0 equation:


Simplifying
(1 + -3i)(1 + 3i) = 0

Multiply (1 + -3i) * (1 + 3i)
(1(1 + 3i) + -3i * (1 + 3i)) = 0
((1 * 1 + 3i * 1) + -3i * (1 + 3i)) = 0
((1 + 3i) + -3i * (1 + 3i)) = 0
(1 + 3i + (1 * -3i + 3i * -3i)) = 0
(1 + 3i + (-3i + -9i2)) = 0

Combine like terms: 3i + -3i = 0
(1 + 0 + -9i2) = 0
(1 + -9i2) = 0

Solving
1 + -9i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -9i2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -9i2 = 0 + -1
-9i2 = 0 + -1

Combine like terms: 0 + -1 = -1
-9i2 = -1

Divide each side by '-9'.
i2 = 0.1111111111

Simplifying
i2 = 0.1111111111

Take the square root of each side:
i = {-0.333333333, 0.333333333}

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