(1-2i)z=2z-i(2+i)

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Solution for (1-2i)z=2z-i(2+i) equation: 


Simplifying
(1 + -2i) * z = 2z + -1i(2 + i)

Reorder the terms for easier multiplication:
z(1 + -2i) = 2z + -1i(2 + i)
(1 * z + -2i * z) = 2z + -1i(2 + i)

Reorder the terms:
(-2iz + 1z) = 2z + -1i(2 + i)
(-2iz + 1z) = 2z + -1i(2 + i)
-2iz + 1z = 2z + (2 * -1i + i * -1i)
-2iz + 1z = 2z + (-2i + -1i2)

Reorder the terms:
-2iz + 1z = -2i + -1i2 + 2z

Solving
-2iz + 1z = -2i + -1i2 + 2z

Solving for variable 'i'.

Reorder the terms:
2i + -2iz + i2 + 1z + -2z = -2i + -1i2 + 2z + 2i + i2 + -2z

Combine like terms: 1z + -2z = -1z
2i + -2iz + i2 + -1z = -2i + -1i2 + 2z + 2i + i2 + -2z

Reorder the terms:
2i + -2iz + i2 + -1z = -2i + 2i + -1i2 + i2 + 2z + -2z

Combine like terms: -2i + 2i = 0
2i + -2iz + i2 + -1z = 0 + -1i2 + i2 + 2z + -2z
2i + -2iz + i2 + -1z = -1i2 + i2 + 2z + -2z

Combine like terms: -1i2 + i2 = 0
2i + -2iz + i2 + -1z = 0 + 2z + -2z
2i + -2iz + i2 + -1z = 2z + -2z

Combine like terms: 2z + -2z = 0
2i + -2iz + i2 + -1z = 0

The solution to this equation could not be determined.

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