(1-2i)(1+3i)=0

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Solution for (1-2i)(1+3i)=0 equation:


Simplifying
(1 + -2i)(1 + 3i) = 0

Multiply (1 + -2i) * (1 + 3i)
(1(1 + 3i) + -2i * (1 + 3i)) = 0
((1 * 1 + 3i * 1) + -2i * (1 + 3i)) = 0
((1 + 3i) + -2i * (1 + 3i)) = 0
(1 + 3i + (1 * -2i + 3i * -2i)) = 0
(1 + 3i + (-2i + -6i2)) = 0

Combine like terms: 3i + -2i = 1i
(1 + 1i + -6i2) = 0

Solving
1 + 1i + -6i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(1 + -2i)(1 + 3i) = 0

Subproblem 1

Set the factor '(1 + -2i)' equal to zero and attempt to solve: Simplifying 1 + -2i = 0 Solving 1 + -2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2i = 0 + -1 -2i = 0 + -1 Combine like terms: 0 + -1 = -1 -2i = -1 Divide each side by '-2'. i = 0.5 Simplifying i = 0.5

Subproblem 2

Set the factor '(1 + 3i)' equal to zero and attempt to solve: Simplifying 1 + 3i = 0 Solving 1 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3i = 0 + -1 3i = 0 + -1 Combine like terms: 0 + -1 = -1 3i = -1 Divide each side by '3'. i = -0.3333333333 Simplifying i = -0.3333333333

Solution

i = {0.5, -0.3333333333}

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