(1+z)(3z+2)=0

Solution for (1+z)(3z+2)=0 equation:

Simplifying
(1 + z)(3z + 2) = 0

Reorder the terms:
(1 + z)(2 + 3z) = 0

Multiply (1 + z) * (2 + 3z)
(1(2 + 3z) + z(2 + 3z)) = 0
((2 * 1 + 3z * 1) + z(2 + 3z)) = 0
((2 + 3z) + z(2 + 3z)) = 0
(2 + 3z + (2 * z + 3z * z)) = 0
(2 + 3z + (2z + 3z2)) = 0

Combine like terms: 3z + 2z = 5z
(2 + 5z + 3z2) = 0

Solving
2 + 5z + 3z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(1 + z)(2 + 3z) = 0

Subproblem 1
Set the factor '(1 + z)' equal to zero and attempt to solve:

Simplifying
1 + z = 0

Solving
1 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + z = 0 + -1
z = 0 + -1

Combine like terms: 0 + -1 = -1
z = -1

Simplifying
z = -1
Subproblem 2
Set the factor '(2 + 3z)' equal to zero and attempt to solve:

Simplifying
2 + 3z = 0

Solving
2 + 3z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 3z = 0 + -2
3z = 0 + -2

Combine like terms: 0 + -2 = -2
3z = -2

Divide each side by '3'.
z = -0.6666666667

Simplifying
z = -0.6666666667
Solution
z = {-1, -0.6666666667}