(1+z)(2z-5)=0

Solution for (1+z)(2z-5)=0 equation:

Simplifying
(1 + z)(2z + -5) = 0

Reorder the terms:
(1 + z)(-5 + 2z) = 0

Multiply (1 + z) * (-5 + 2z)
(1(-5 + 2z) + z(-5 + 2z)) = 0
((-5 * 1 + 2z * 1) + z(-5 + 2z)) = 0
((-5 + 2z) + z(-5 + 2z)) = 0
(-5 + 2z + (-5 * z + 2z * z)) = 0
(-5 + 2z + (-5z + 2z2)) = 0

Combine like terms: 2z + -5z = -3z
(-5 + -3z + 2z2) = 0

Solving
-5 + -3z + 2z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(-1 + -1z)(5 + -2z) = 0

Subproblem 1
Set the factor '(-1 + -1z)' equal to zero and attempt to solve:

Simplifying
-1 + -1z = 0

Solving
-1 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1z = 0 + 1
-1z = 0 + 1

Combine like terms: 0 + 1 = 1
-1z = 1

Divide each side by '-1'.
z = -1

Simplifying
z = -1
Subproblem 2
Set the factor '(5 + -2z)' equal to zero and attempt to solve:

Simplifying
5 + -2z = 0

Solving
5 + -2z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -2z = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2z = 0 + -5
-2z = 0 + -5

Combine like terms: 0 + -5 = -5
-2z = -5

Divide each side by '-2'.
z = 2.5

Simplifying
z = 2.5
Solution
z = {-1, 2.5}