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(1+x/6x)=(1/3)
We move all terms to the left:
(1+x/6x)-((1/3))=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(x/6x+1)-((+1/3))=0
We get rid of parentheses
x/6x+1-((+1/3))=0
We calculate fractions
3x^2/18x^2+(-((+1*6x)/18x^2+1=0
We calculate fractions
We do not support expression: x^4
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