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(1+x)3=15+x
We move all terms to the left:
(1+x)3-(15+x)=0
We add all the numbers together, and all the variables
(x+1)3-(x+15)=0
We multiply parentheses
3x-(x+15)+3=0
We get rid of parentheses
3x-x-15+3=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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