(1+x)(3+2x)=

Solution for (1+x)(3+2x)= equation:

Simplifying
(1 + x)(3 + 2x) = 0

Multiply (1 + x) * (3 + 2x)
(1(3 + 2x) + x(3 + 2x)) = 0
((3 * 1 + 2x * 1) + x(3 + 2x)) = 0
((3 + 2x) + x(3 + 2x)) = 0
(3 + 2x + (3 * x + 2x * x)) = 0
(3 + 2x + (3x + 2x2)) = 0

Combine like terms: 2x + 3x = 5x
(3 + 5x + 2x2) = 0

Solving
3 + 5x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + 2x)(1 + x) = 0

Subproblem 1
Set the factor '(3 + 2x)' equal to zero and attempt to solve:

Simplifying
3 + 2x = 0

Solving
3 + 2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2x = 0 + -3
2x = 0 + -3

Combine like terms: 0 + -3 = -3
2x = -3

Divide each side by '2'.
x = -1.5

Simplifying
x = -1.5
Subproblem 2
Set the factor '(1 + x)' equal to zero and attempt to solve:

Simplifying
1 + x = 0

Solving
1 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + x = 0 + -1
x = 0 + -1

Combine like terms: 0 + -1 = -1
x = -1

Simplifying
x = -1
Solution
x = {-1.5, -1}