(1+u)(7+3u)=0

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Solution for (1+u)(7+3u)=0 equation:


Simplifying
(1 + u)(7 + 3u) = 0

Multiply (1 + u) * (7 + 3u)
(1(7 + 3u) + u(7 + 3u)) = 0
((7 * 1 + 3u * 1) + u(7 + 3u)) = 0
((7 + 3u) + u(7 + 3u)) = 0
(7 + 3u + (7 * u + 3u * u)) = 0
(7 + 3u + (7u + 3u2)) = 0

Combine like terms: 3u + 7u = 10u
(7 + 10u + 3u2) = 0

Solving
7 + 10u + 3u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(7 + 3u)(1 + u) = 0

Subproblem 1

Set the factor '(7 + 3u)' equal to zero and attempt to solve: Simplifying 7 + 3u = 0 Solving 7 + 3u = 0 Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 3u = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 3u = 0 + -7 3u = 0 + -7 Combine like terms: 0 + -7 = -7 3u = -7 Divide each side by '3'. u = -2.333333333 Simplifying u = -2.333333333

Subproblem 2

Set the factor '(1 + u)' equal to zero and attempt to solve: Simplifying 1 + u = 0 Solving 1 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + u = 0 + -1 Combine like terms: 1 + -1 = 0 0 + u = 0 + -1 u = 0 + -1 Combine like terms: 0 + -1 = -1 u = -1 Simplifying u = -1

Solution

u = {-2.333333333, -1}

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