(1+i)z=3-i

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Solution for (1+i)z=3-i equation:


Simplifying
(1 + i) * z = 3 + -1i

Reorder the terms for easier multiplication:
z(1 + i) = 3 + -1i
(1 * z + i * z) = 3 + -1i

Reorder the terms:
(iz + 1z) = 3 + -1i
(iz + 1z) = 3 + -1i

Solving
iz + 1z = 3 + -1i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'i' to each side of the equation.
iz + i + 1z = 3 + -1i + i

Reorder the terms:
i + iz + 1z = 3 + -1i + i

Combine like terms: -1i + i = 0
i + iz + 1z = 3 + 0
i + iz + 1z = 3

Add '-1z' to each side of the equation.
i + iz + 1z + -1z = 3 + -1z

Combine like terms: 1z + -1z = 0
i + iz + 0 = 3 + -1z
i + iz = 3 + -1z

Reorder the terms:
-3 + i + iz + z = 3 + -1z + -3 + z

Reorder the terms:
-3 + i + iz + z = 3 + -3 + -1z + z

Combine like terms: 3 + -3 = 0
-3 + i + iz + z = 0 + -1z + z
-3 + i + iz + z = -1z + z

Combine like terms: -1z + z = 0
-3 + i + iz + z = 0

The solution to this equation could not be determined.

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