(1+i)z-(4+i)(5-i)=0

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Solution for (1+i)z-(4+i)(5-i)=0 equation: 


Simplifying
(1 + i) * z + -1(4 + i)(5 + -1i) = 0

Reorder the terms for easier multiplication:
z(1 + i) + -1(4 + i)(5 + -1i) = 0
(1 * z + i * z) + -1(4 + i)(5 + -1i) = 0

Reorder the terms:
(iz + 1z) + -1(4 + i)(5 + -1i) = 0
(iz + 1z) + -1(4 + i)(5 + -1i) = 0

Multiply (4 + i) * (5 + -1i)
iz + 1z + -1(4(5 + -1i) + i(5 + -1i)) = 0
iz + 1z + -1((5 * 4 + -1i * 4) + i(5 + -1i)) = 0
iz + 1z + -1((20 + -4i) + i(5 + -1i)) = 0
iz + 1z + -1(20 + -4i + (5 * i + -1i * i)) = 0
iz + 1z + -1(20 + -4i + (5i + -1i2)) = 0

Combine like terms: -4i + 5i = 1i
iz + 1z + -1(20 + 1i + -1i2) = 0
iz + 1z + (20 * -1 + 1i * -1 + -1i2 * -1) = 0
iz + 1z + (-20 + -1i + 1i2) = 0

Reorder the terms:
-20 + -1i + iz + 1i2 + 1z = 0

Solving
-20 + -1i + iz + 1i2 + 1z = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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